Monday, November 9, 2015

November 9, 2015

Use the solubility product constant table (available under the resources tab on Oncourse) to answer the following question:

Which substance is more soluble in a pure sample of water: barium carbonate or lead(II) carbonate?

Explain your answer and ask another question about solubility equilibrium for the next person to answer.

9 comments:

  1. i believe that barium carbonate is more soluble... what is one way to increase the solubility of a compound

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    Replies
    1. What support do you have for your belief?
      Let's say what is one way to increase the solubility of CaCO3?

      Delete
  2. One way to increase the solubility of CaCO3 is to add an acid.

    What is the most insoluble compound of the SP chart?

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  3. The lower the Ksp value the more insoluble it is. So, Mercury(II) sulfide with a Ksp of 2 x 10^-53 would be the most insoluble.

    What does it mean if a solution is saturated?

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  4. A solution is saturated when dissolved solute is in dynamic equilibrium with any undissolved solute, and any added solute will therefore not dissolve.

    What factors affect the solubility product constant, Ksp?

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  5. Temperature is a factor that effects the solubility product constant.

    How do you find the molar solubility, S, of Calcium chromate.

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  6. Molar solubility is calculated using the Ksp value and stoichiometry.

    What is the most soluble compound on the SP chart?

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  7. The most soluble would be the calcium chromate because it has the highest listed Ksp value. The larger this value, the more soluble it is.

    What could you do to decrease the solubility of calcium chromate?

    ReplyDelete